W e examine this locus for a general isosceles triangle, whose vertices are located at (-a,0), (a,0) and (0,b). We parameterize the family by forcing them to also pass through the point (-2,t).
The locus of the midpoint of the conic is a circle. A mere coffee break won’t do it for this calculation - this one takes more like a lunch break!
Expressions
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| Hyperbola Eq |  |
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